Optimal. Leaf size=87 \[ \frac{b^2 (6 a+5 b) \tan ^{-1}(\sinh (c+d x))}{2 d}+\frac{(a+b)^3 \sinh ^3(c+d x)}{3 d}+\frac{(a-2 b) (a+b)^2 \sinh (c+d x)}{d}-\frac{b^3 \tanh (c+d x) \text{sech}(c+d x)}{2 d} \]
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Rubi [A] time = 0.105108, antiderivative size = 87, normalized size of antiderivative = 1., number of steps used = 5, number of rules used = 4, integrand size = 23, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.174, Rules used = {3676, 390, 385, 203} \[ \frac{b^2 (6 a+5 b) \tan ^{-1}(\sinh (c+d x))}{2 d}+\frac{(a+b)^3 \sinh ^3(c+d x)}{3 d}+\frac{(a-2 b) (a+b)^2 \sinh (c+d x)}{d}-\frac{b^3 \tanh (c+d x) \text{sech}(c+d x)}{2 d} \]
Antiderivative was successfully verified.
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Rule 3676
Rule 390
Rule 385
Rule 203
Rubi steps
\begin{align*} \int \cosh ^3(c+d x) \left (a+b \tanh ^2(c+d x)\right )^3 \, dx &=\frac{\operatorname{Subst}\left (\int \frac{\left (a+(a+b) x^2\right )^3}{\left (1+x^2\right )^2} \, dx,x,\sinh (c+d x)\right )}{d}\\ &=\frac{\operatorname{Subst}\left (\int \left ((a-2 b) (a+b)^2+(a+b)^3 x^2+\frac{b^2 (3 a+2 b)+3 b^2 (a+b) x^2}{\left (1+x^2\right )^2}\right ) \, dx,x,\sinh (c+d x)\right )}{d}\\ &=\frac{(a-2 b) (a+b)^2 \sinh (c+d x)}{d}+\frac{(a+b)^3 \sinh ^3(c+d x)}{3 d}+\frac{\operatorname{Subst}\left (\int \frac{b^2 (3 a+2 b)+3 b^2 (a+b) x^2}{\left (1+x^2\right )^2} \, dx,x,\sinh (c+d x)\right )}{d}\\ &=\frac{(a-2 b) (a+b)^2 \sinh (c+d x)}{d}+\frac{(a+b)^3 \sinh ^3(c+d x)}{3 d}-\frac{b^3 \text{sech}(c+d x) \tanh (c+d x)}{2 d}+\frac{\left (b^2 (6 a+5 b)\right ) \operatorname{Subst}\left (\int \frac{1}{1+x^2} \, dx,x,\sinh (c+d x)\right )}{2 d}\\ &=\frac{b^2 (6 a+5 b) \tan ^{-1}(\sinh (c+d x))}{2 d}+\frac{(a-2 b) (a+b)^2 \sinh (c+d x)}{d}+\frac{(a+b)^3 \sinh ^3(c+d x)}{3 d}-\frac{b^3 \text{sech}(c+d x) \tanh (c+d x)}{2 d}\\ \end{align*}
Mathematica [C] time = 6.90058, size = 494, normalized size = 5.68 \[ \frac{\text{csch}^5(c+d x) \left (-256 \sinh ^8(c+d x) \left (a \sinh ^2(c+d x)+a+b \sinh ^2(c+d x)\right )^3 \text{HypergeometricPFQ}\left (\left \{\frac{3}{2},2,2,2,2\right \},\left \{1,1,1,\frac{11}{2}\right \},-\sinh ^2(c+d x)\right )+21 \left (3 a^2 b \left (753 \sinh ^8(c+d x)+18826 \sinh ^6(c+d x)+69728 \sinh ^4(c+d x)+88150 \sinh ^2(c+d x)+36015\right ) \sinh ^2(c+d x)+a^3 \left (753 \sinh ^{10}(c+d x)+19579 \sinh ^8(c+d x)+89514 \sinh ^6(c+d x)+157878 \sinh ^4(c+d x)+124165 \sinh ^2(c+d x)+36015\right )+3 a b^2 \left (753 \sinh ^6(c+d x)+18073 \sinh ^4(c+d x)+50695 \sinh ^2(c+d x)+36015\right ) \sinh ^4(c+d x)+b^3 \left (753 \sinh ^4(c+d x)+17320 \sinh ^2(c+d x)+32415\right ) \sinh ^6(c+d x)\right )-\frac{315 \tanh ^{-1}\left (\sqrt{-\sinh ^2(c+d x)}\right ) \left (3 a^2 b \left (\sinh ^3(c+d x)+\sinh (c+d x)\right )^2 \left (\sinh ^6(c+d x)+243 \sinh ^4(c+d x)+1875 \sinh ^2(c+d x)+2401\right )+a^3 \left (\sinh ^6(c+d x)+243 \sinh ^4(c+d x)+1875 \sinh ^2(c+d x)+2401\right ) \cosh ^6(c+d x)+3 a b^2 \sinh ^4(c+d x) \left (\sinh ^8(c+d x)+244 \sinh ^6(c+d x)+2118 \sinh ^4(c+d x)+4180 \sinh ^2(c+d x)+2401\right )+b^3 \sinh ^6(c+d x) \left (\sinh ^6(c+d x)+243 \sinh ^4(c+d x)+1875 \sinh ^2(c+d x)+2161\right )\right )}{\sqrt{-\sinh ^2(c+d x)}}\right )}{30240 d} \]
Warning: Unable to verify antiderivative.
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Maple [B] time = 0.044, size = 227, normalized size = 2.6 \begin{align*}{\frac{2\,{a}^{3}\sinh \left ( dx+c \right ) }{3\,d}}+{\frac{{a}^{3}\sinh \left ( dx+c \right ) \left ( \cosh \left ( dx+c \right ) \right ) ^{2}}{3\,d}}+{\frac{{a}^{2}b \left ( \cosh \left ( dx+c \right ) \right ) ^{2}\sinh \left ( dx+c \right ) }{d}}-{\frac{{a}^{2}b\sinh \left ( dx+c \right ) }{d}}+{\frac{a{b}^{2} \left ( \sinh \left ( dx+c \right ) \right ) ^{3}}{d}}+6\,{\frac{a{b}^{2}\arctan \left ({{\rm e}^{dx+c}} \right ) }{d}}-3\,{\frac{a{b}^{2}\sinh \left ( dx+c \right ) }{d}}+{\frac{{b}^{3} \left ( \sinh \left ( dx+c \right ) \right ) ^{5}}{3\,d \left ( \cosh \left ( dx+c \right ) \right ) ^{2}}}-{\frac{5\,{b}^{3} \left ( \sinh \left ( dx+c \right ) \right ) ^{3}}{3\,d \left ( \cosh \left ( dx+c \right ) \right ) ^{2}}}-5\,{\frac{{b}^{3}\sinh \left ( dx+c \right ) }{d \left ( \cosh \left ( dx+c \right ) \right ) ^{2}}}+{\frac{5\,{b}^{3}{\rm sech} \left (dx+c\right )\tanh \left ( dx+c \right ) }{2\,d}}+5\,{\frac{{b}^{3}\arctan \left ({{\rm e}^{dx+c}} \right ) }{d}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [B] time = 1.66538, size = 383, normalized size = 4.4 \begin{align*} \frac{a^{2} b{\left (e^{\left (d x + c\right )} - e^{\left (-d x - c\right )}\right )}^{3}}{8 \, d} - \frac{1}{8} \, a b^{2}{\left (\frac{{\left (15 \, e^{\left (-2 \, d x - 2 \, c\right )} - 1\right )} e^{\left (3 \, d x + 3 \, c\right )}}{d} - \frac{15 \, e^{\left (-d x - c\right )} - e^{\left (-3 \, d x - 3 \, c\right )}}{d} + \frac{48 \, \arctan \left (e^{\left (-d x - c\right )}\right )}{d}\right )} + \frac{1}{24} \, b^{3}{\left (\frac{27 \, e^{\left (-d x - c\right )} - e^{\left (-3 \, d x - 3 \, c\right )}}{d} - \frac{120 \, \arctan \left (e^{\left (-d x - c\right )}\right )}{d} - \frac{25 \, e^{\left (-2 \, d x - 2 \, c\right )} + 77 \, e^{\left (-4 \, d x - 4 \, c\right )} + 3 \, e^{\left (-6 \, d x - 6 \, c\right )} - 1}{d{\left (e^{\left (-3 \, d x - 3 \, c\right )} + 2 \, e^{\left (-5 \, d x - 5 \, c\right )} + e^{\left (-7 \, d x - 7 \, c\right )}\right )}}\right )} + \frac{1}{24} \, a^{3}{\left (\frac{e^{\left (3 \, d x + 3 \, c\right )}}{d} + \frac{9 \, e^{\left (d x + c\right )}}{d} - \frac{9 \, e^{\left (-d x - c\right )}}{d} - \frac{e^{\left (-3 \, d x - 3 \, c\right )}}{d}\right )} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [B] time = 2.20745, size = 4523, normalized size = 51.99 \begin{align*} \text{result too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [B] time = 2.4196, size = 377, normalized size = 4.33 \begin{align*} \frac{24 \,{\left (6 \, a b^{2} e^{c} + 5 \, b^{3} e^{c}\right )} \arctan \left (e^{\left (d x + c\right )}\right ) e^{\left (-c\right )} -{\left (9 \, a^{3} e^{\left (2 \, d x + 2 \, c\right )} - 9 \, a^{2} b e^{\left (2 \, d x + 2 \, c\right )} - 45 \, a b^{2} e^{\left (2 \, d x + 2 \, c\right )} - 27 \, b^{3} e^{\left (2 \, d x + 2 \, c\right )} + a^{3} + 3 \, a^{2} b + 3 \, a b^{2} + b^{3}\right )} e^{\left (-3 \, d x - 3 \, c\right )} +{\left (a^{3} e^{\left (3 \, d x + 30 \, c\right )} + 3 \, a^{2} b e^{\left (3 \, d x + 30 \, c\right )} + 3 \, a b^{2} e^{\left (3 \, d x + 30 \, c\right )} + b^{3} e^{\left (3 \, d x + 30 \, c\right )} + 9 \, a^{3} e^{\left (d x + 28 \, c\right )} - 9 \, a^{2} b e^{\left (d x + 28 \, c\right )} - 45 \, a b^{2} e^{\left (d x + 28 \, c\right )} - 27 \, b^{3} e^{\left (d x + 28 \, c\right )}\right )} e^{\left (-27 \, c\right )} - \frac{24 \,{\left (b^{3} e^{\left (3 \, d x + 3 \, c\right )} - b^{3} e^{\left (d x + c\right )}\right )}}{{\left (e^{\left (2 \, d x + 2 \, c\right )} + 1\right )}^{2}}}{24 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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